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4-55x-14x^2=0
a = -14; b = -55; c = +4;
Δ = b2-4ac
Δ = -552-4·(-14)·4
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3249}=57$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-57}{2*-14}=\frac{-2}{-28} =1/14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+57}{2*-14}=\frac{112}{-28} =-4 $
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